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If both the source and sink tempreature are decereased by the same amount in a carnot engine .It effeciency is
The efficiency of carnot engine is given byT1-T2/2.Let t1 be increased by x and so t2So efficiency beT1+x-(T2+x)/T1+xT1-T2/T1+xAs the denominator value is increased,the total value of efficiency decreases
The efficiency of carnot engine is given by
T1-T2/2.
Let t1 be increased by x and so t2
So efficiency be
T1+x-(T2+x)/T1+x
T1-T2/T1+x
As the denominator value is increased,the total value of efficiency decreases
DEAR STUDENT,T1-T2/T1=ETA1= EFFICIENCY OF HEAT ENGINE(T1-X)- (T2-X)/T1-X = ETA2= EFFICIENCY OF HEAT ENGINE AFTER DECREASING TEMPERATUREON SOLVING , ETA1/ETA2= T1-X/T1
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