If both the source and sink tempreature are decereased by the same amount in a carnot engine .It effeciency is

Question

Arun · Answer

The efficiency of carnot engine is given by

T1-T2/2.

Let t1 be increased by x and so t2

So efficiency be

T1+x-(T2+x)/T1+x

T1-T2/T1+x

As the denominator value is increased,the total value of efficiency decreases

Aastha Singh · Answer

DEAR STUDENT, T 1 -T 2 /T 1 =ETA 1 = EFFICIENCY OF HEAT ENGINE (T 1 -X)- (T 2 -X)/T 1 -X = ETA 2 = EFFICIENCY OF HEAT ENGINE AFTER DECREASING TEMPERATURE ON SOLVING , ETA 1 /ETA 2 = T 1 -X/T 1

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If both the source and sink tempreature are decereased by the same amount in a carnot engine .It effeciency is

If both the source and sink tempreature are decereased by the same amount in a carnot engine .It effeciency is

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