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Grade 11Thermal Physics

If both the source and sink tempreature are decereased by the same amount in a carnot engine .It effeciency is

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Profile image of koduru vasu
7 Years agoGrade 11
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2 Answers

Profile image of Arun
7 Years ago

The efficiency of carnot engine is given by

T1-T2/2.

Let t1 be increased by x and so t2

So efficiency be

T1+x-(T2+x)/T1+x

T1-T2/T1+x

As the denominator value is increased,the total value of efficiency decreases

Profile image of Aastha Singh
7 Years ago
DEAR STUDENT,
T1-T2/T1=ETA1= EFFICIENCY OF HEAT ENGINE
(T1-X)- (T2-X)/T1-X = ETA2= EFFICIENCY OF HEAT ENGINE AFTER DECREASING TEMPERATURE
ON SOLVING , ETA1/ETA2= T1-X/T1

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