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If both the source and sink tempreature are decereased by the same amount in a carnot engine .It effeciency is
The efficiency of carnot engine is given byT1-T2/2.Let t1 be increased by x and so t2So efficiency beT1+x-(T2+x)/T1+xT1-T2/T1+xAs the denominator value is increased,the total value of efficiency decreases
The efficiency of carnot engine is given by
T1-T2/2.
Let t1 be increased by x and so t2
So efficiency be
T1+x-(T2+x)/T1+x
T1-T2/T1+x
As the denominator value is increased,the total value of efficiency decreases
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