If an iron ray has a length of 100m when the temperature is 10°c by how much will it expand when the temperature rises to 30°c. Take linear expansivity of iron as 0.000012/degree celcius

Meep
13 Points
5 years ago
L2=L1(1+ coefficient of linear expansion(t2-t1))
=100*(1+0.000012(30-10))
=100.024
Thus, it expands by L2-L1 metres = 0.024m

Rajdeep
231 Points
5 years ago
HELLO THERE!
Let’s collect the given data first.
Here’s what we are given:

Length of the iron rod (L) = 100m
Coefficient of linear expansion ($\dpi{80} \alpha$) = $\dpi{80} 1.2\times 10^{-5}$
Rise in temperature = 20 K

Now,
$\triangle L = L \alpha \triangle T = 100 \times 1.2 \times 10^{-5} \times 20 \\= 2.4 \times 10^{-2} m$

THANKS!
Bdya Poudel
15 Points
3 years ago
Initial length of iron(L1)=100m
Initial temperature(T1)=10°C
Final omelette(T2)=40°C
Now,
Difference in length of iron between 40°C and 10°C=L1*alpha *∆T
=100*1.13*10^-5*30
=0.039
If there is the error of 0.039 in 100m,then in 2 Km I.e.2000m,there will be the error of=0.039*2000/100
=0.78,,and//