If an iron ray has a length of 100m when the temperature is 10°c by how much will it expand when the temperature rises to 30°c. Take linear expansivity of iron as 0.000012/degree celcius

Question

Meep · Answer

L2=L1(1+ coefficient of linear expansion(t2-t1)) =100*(1+0.000012(30-10)) =100.024 Thus, it expands by L2-L1 metres = 0.024m

Rajdeep · Answer

HELLO THERE! Let’s collect the given data first. Here’s what we are given: Length of the iron rod (L) = 100m Coefficient of linear expansion ( ) = Rise in temperature = 20 K Now, THANKS!

Bdya Poudel · Answer

Initial length of iron(L1)=100m Initial temperature(T1)=10°C Final omelette(T2)=40°C Now, Difference in length of iron between 40°C and 10°C=L1*alpha *∆T =100*1.13*10^-5*30 =0.039 If there is the error of 0.039 in 100m,then in 2 Km I.e.2000m,there will be the error of=0.039*2000/100 =0.78,,and//

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If an iron ray has a length of 100m when the temperature is 10°c by how much will it expand when the temperature rises to 30°c. Take linear expansivity of iron as 0.000012/degree celcius

If an iron ray has a length of 100m when the temperature is 10°c by how much will it expand when the temperature rises to 30°c. Take linear expansivity of iron as 0.000012/degree celcius

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