if 10g of the ice at 0 degree celcius is mixed with 10g of water at 100 degree celcius ,then the final temperature of the mixture will be

Latent heat of fusion of ice = 336 J/gspecific heat of water = 4.186 J/g degreeCFirst 10g ice melts and then its temperature increases by gaining heat from 100g water. let the resultant temperature is T.Energy gained by 10g ice = energy lost by 10g water10*(336) + 10*4.186*(T-0) = 100*4.186*(100-T)3360 + 41.86 T …..