Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Ice of mass 2kg at -20°C and 5 kg of water at 20°C are mixed (specific heat of water = 1 Cal/g°C ,specific heat of ice = 0.5 Cal/g°C).Find the net amount of water in the container.

Ice of mass 2kg at -20°C and 5 kg of water at 20°C are mixed (specific heat of water = 1 Cal/g°C ,specific heat of ice = 0.5 Cal/g°C).Find the net amount of water in the container.

Grade:12th pass

1 Answers

Abhishek Kumar
askIITians Faculty 253 Points
6 years ago
Let the mass of ice converted to water be m.
So, 1000mL = (5+m)1000 x 1 x (T-293)

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free