how to approach these type of questions I calculated the total heat taken by water divided by the latent heat of vapourisation which gives the mass of steam converted into water but the ans isn’t matching

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Arun · Answer

heat needed to melt the ice = mL = 1* 3.36*100000 =336000 J heat needed to increase the temperature of water to 100 degree centigrade=1*4200=4200 J total heat requirement= 340200 suppose m mass of steam is converted in to water then m*2260000= 340200 m= 340200/2260000=150.5 g final composition water=1150.5 g & steam=849.5 g

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how to approach these type of questions I calculated the total heat taken by water divided by the latent heat of vapourisation which gives the mass of steam converted into water but the ans isn’t matching

how to approach these type of questions
I calculated the total heat taken by water divided by the latent heat of vapourisation which gives the mass of steam converted into water but the ans isn’t matching

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