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how to approach these type of questions
I calculated the total heat taken by water divided by the latent heat of vapourisation which gives the mass of steam converted into water but the ans isn’t matching

abzz reign , 7 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 7 Years ago

heat needed to melt the ice = mL = 1* 3.36*100000 =336000 J heat needed to increase the temperature of water to 100 degree centigrade=1*4200=4200 J total heat requirement= 340200 suppose m mass of steam is converted in to water then m*2260000= 340200 m= 340200/2260000=150.5 g final composition water=1150.5 g & steam=849.5 g

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