Flag Thermal Physics> Help me out with these two problems plz!!...
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Help me out with these two problems plz!!


1) A glass window is to be fitted in an aluminium frame.The temperature on the wrkin day is 40C and the glass window measures exactly 20cm x 30cm.What shld b d size of d aluminium frame so dat thr is no stress on the glass in winter even if the temperature drops to 0C ? Co-effificients of linear exp of glass nd aluminium are 9.0 x 10^-6 /C and 24 x 10^-6 /C respectively.



2)A pendulum clock gives correct time at 20C at a place where g=9.800m/s^2. The pendulum consists of a li8 steel rod connected 2 a heavy ball.It is taken 2 a different place where g=9.788m/s^2. At what temperature will it give correct time? Co-efficient of linear expansion of steel = 12 x 10^-6 /C.

Navjyot Kalra , 12 Years ago
Grade 10
anser 1 Answers
Askiitians Tutor Team

Let's tackle these two problems step by step, ensuring we understand the concepts of thermal expansion and how they apply to each scenario.

Problem 1: Sizing the Aluminium Frame

In this situation, we need to ensure that the glass window can expand and contract without causing stress on it due to temperature changes. The key here is to calculate how much the glass and the aluminium frame will expand or contract with temperature changes.

Step 1: Calculate the change in temperature

The temperature change (ΔT) from summer to winter is:

  • Summer temperature = 40°C
  • Winter temperature = 0°C
  • ΔT = 0°C - 40°C = -40°C

Step 2: Calculate the dimensions of the glass window

The dimensions of the glass window are:

  • Width (W) = 20 cm
  • Height (H) = 30 cm

Step 3: Calculate the expansion of glass

The formula for linear expansion is:

ΔL = L₀ * α * ΔT

Where:

  • ΔL = change in length
  • L₀ = original length
  • α = coefficient of linear expansion
  • ΔT = change in temperature

For glass:

  • α (glass) = 9.0 x 10-6 /°C
  • ΔL (width) = 20 cm * 9.0 x 10-6 /°C * (-40°C) = -0.00072 cm
  • ΔL (height) = 30 cm * 9.0 x 10-6 /°C * (-40°C) = -0.00108 cm

Step 4: Calculate the expansion of aluminium

Now, let's calculate how much the aluminium frame will expand:

  • α (aluminium) = 24 x 10-6 /°C
  • ΔL (width) = 20 cm * 24 x 10-6 /°C * (-40°C) = -0.00192 cm
  • ΔL (height) = 30 cm * 24 x 10-6 /°C * (-40°C) = -0.00288 cm

Step 5: Determine the size of the aluminium frame

To ensure that the glass does not experience stress, the frame must be larger than the glass when the temperature drops. Therefore, we need to add the expansion of the glass to its original dimensions:

  • New width = 20 cm + 0.00072 cm = 20.00072 cm
  • New height = 30 cm + 0.00108 cm = 30.00108 cm

Thus, the size of the aluminium frame should be approximately:

  • Width = 20.00072 cm
  • Height = 30.00108 cm

Problem 2: Correcting the Pendulum Clock

For the second problem, we need to find the temperature at which the pendulum clock will give the correct time at a different gravitational field strength.

Step 1: Understand the relationship between pendulum length and gravity

The period of a pendulum is given by:

T = 2π√(L/g)

Where:

  • T = period of the pendulum
  • L = length of the pendulum
  • g = acceleration due to gravity

Step 2: Set up the equation for the two locations

At the original location:

  • g₁ = 9.800 m/s²
  • T₁ = 2π√(L/g₁)

At the new location:

  • g₂ = 9.788 m/s²
  • T₂ = 2π√(L/g₂)

Step 3: Relate the periods

Since the clock gives the correct time at 20°C, we can set T₁ = T₂:

2π√(L/g₁) = 2π√(L/g₂)

This simplifies to:

√(L/g₁) = √(L/g₂)

Squaring both sides gives:

L/g₁ = L/g₂

Thus, we can express the relationship as:

g₁/g₂ = (1 + αΔT)

Where α is the coefficient of linear expansion of steel.

Step 4: Solve for the temperature change

Rearranging gives:

ΔT = (g₁/g₂ - 1) / α

Substituting the values:

  • α = 12 x 10-6 /°C
  • ΔT = (9.800 / 9.788 - 1) / (12 x 10-6)

Calculating this gives:

ΔT ≈ 0.00122 / (12 x 10-6) ≈ 101.67°C

Step 5: Determine the new temperature

Since the clock was correct at 20°C, we need to add the temperature change:

New temperature = 20°C + 101.67°C ≈ 121.67°C

In summary, the aluminium frame should be approximately 20.00072 cm by 30.00108 cm to accommodate the glass window without stress, and the pendulum clock will give the correct time

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