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Half life of a certain radioactive substance is 69.3 days. Its disintegration constant is:

Jai Mahyavanshi , 8 Years ago
Grade 12
anser 2 Answers
Adarsh
Dear student,
half life for 1st order reaction = 0.693/k
so   69.3=0.693/k    => k= 100.
Thanks and Regards 
Adarsh
 
Last Activity: 8 Years ago
anuragmishra
Half life for first order reaction= 0.693 / K
69.3 = 0.693/K
K= 0.01day-1
Here K is decay constant
Thanks and Regards 
Anurag Misra
Last Activity: 6 Years ago
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