for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is: (1)9.92 Cal (2) 13.90 Cal (3) 19.84 Cal (4) 27.80 Cal

Question

for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is: (1)9.92 Cal (2) 13.90 Cal (3) 19.84 Cal (4) 27.80 Cal

Arun · Answer

Dear student Internal energy change = n * Cv * T = 2 * 4.96 * 2 = 19.84 Cal Regards Arun (askIITians forum expert)

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for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is: (1)9.92 Cal (2) 13.90 Cal (3) 19.84 Cal (4) 27.80 Cal

for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is:
(1)9.92 Cal (2) 13.90 Cal (3) 19.84 Cal (4) 27.80 Cal

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for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is: (1)9.92 Cal (2) 13.90 Cal (3) 19.84 Cal (4) 27.80 Cal

for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is:(1)9.92 Cal (2) 13.90 Cal (3) 19.84 Cal (4) 27.80 Cal

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for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is:
(1)9.92 Cal (2) 13.90 Cal (3) 19.84 Cal (4) 27.80 Cal