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for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is: (1)9.92 Cal (2) 13.90 Cal (3) 19.84 Cal (4) 27.80 Cal

for a gas Cv= 4.96 cal/mole-K when 2 mole gas is heated from 340 K to 342K increase in internal energy is:
(1)9.92 Cal     (2) 13.90 Cal      (3) 19.84 Cal       (4) 27.80 Cal  

Grade:12

1 Answers

Arun
25763 Points
3 years ago
Dear student
 
Internal energy change  = n * Cv * \DeltaT
 = 2 * 4.96 * 2 = 19.84 Cal
 
Regards
Arun (askIITians forum expert)

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