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Five rods of the same dimensions are arranged as shown. They have thermal conductivities k1, k2, k3, k4 and k5. When points A andB are maintained at different temperatures, no heat flows through the central rod. It follows that :(a) k1 = k4 and k2 = k3(b) k1/k4 = k2/k3(c) k1k4 = k2k3(d) k1k2 = k3k4pls rewply fast

Hrishant Goswami , 11 Years ago

Grade 10

1 Answers

anmol tyagi

Last Activity: 7 Years ago

For no current flow between C and D (Qt)AC=(Qt)CB
Þ K1A(θ_A−θ_C)l = K₂A(θ_C−θ_B)l
Þ θ_A−θ_Cθ_C−θ_B = K₂K₁ ...(i) Also (Qt)AD=(Qt)DB
ÞK₃A(θ_A−θ_D)l = K4_A(θ_D−θ_B)l
Þθ_A−θ_Dθ_D−θ_B = K₄K₃ ...(ii) It is given that θ_C=θ_D,
hence from equation (i) and (ii) we get K₂K₁=K₄K₃
Þ K₁K₄ = K₂K₃K₁K₄ = K₂K₃K1K4=K2K3

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