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Grade: 12th pass
        
Find magnitude of work done in cyclic process in attachment........ ... . Ans: π/4(P2-P1)(V2-V1)
5 months ago

Answers : (2)

Arun
20881 Points
							
Dear student
 
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Arun (askIITians forum expert)
5 months ago
Khimraj
2788 Points
							
 
work one is equal to area of PV graph
area of ellipse = \piab
a = (P2 – P1)/2
b = (V2 – V1)/2
so work done = (\pi/4)(P2-P1)(V2-V1)
Hope it clears...............................................................
5 months ago
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