MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: upto college level
        
Consider that 214 J of work are done  on a system, and 293 J of heat are extracted from the system. In the sense of the first law of thermodynamics, what are the values(including algebraic signs) of (a) W, (b) Q, and (C) ∆Eint?
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
							(a) Since work is done on the system, therefore algebraic sign of the work done will be positive and the magnitude of work done is 214 J.
Thus, W = +214 J.
(b) Since heat is extracted from the system, therefore algebraic sign of the heat will be negative and the magnitude of heat is 293 J.
Thus, Q = -293 J.
(c) To obtain internal energy of the system, substitute -293 J for Q and +214 J for W in the equation ΔEint = Q + W,ΔEint = Q + W
= (-293 J) + (+214 J)
= -79.0 J
From the above observation we conclude that, the internal energy of the system would be -79.0 J.


3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 551 off

COUPON CODE: SELF20


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 594 off

COUPON CODE: SELF20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details