Calculate the work done by an external agent in compressing 1.12 mol of oxygen from a volume 22.4 L and 1.32 atm pressure to 15.3 L at the same temperature.

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Navjyot Kalra · Answer

From the above observation we conclude that, the work done by an external agent in compressing the oxygen molecule would be 1.14&times;10 3 J.

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Calculate the work done by an external agent in compressing 1.12 mol of oxygen from a volume 22.4 L and 1.32 atm pressure to 15.3 L at the same temperature.

Calculate the work done by an external agent in compressing 1.12 mol of oxygen from a volume 22.4 L and 1.32 atm pressure to 15.3 L at the same temperature.

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Calculate the work done by an external agent in compressing 1.12 mol of oxygen from a volume 22.4 L and 1.32 atm pressure to 15.3 L at the same temperature.

Calculate the work done by an external agent in compressing 1.12 mol of oxygen from a volume 22.4 L and 1.32 atm pressure to 15.3 L at the same temperature.

1 Answers

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