Calculate the volume of a 1 mole of an ideal gas at STP
Jayant Kumar , 11 Years ago
Grade 11
Thermal Physics> physics...
1 AnswersMukesh Sharma
Last Activity: 11 Years ago
here
STP means the gases have pressure 1atm and Temp of 273 Kelvin
Now we're going to use the equation PV= nRT, where P=pressure, V=volume, n= moles, R= constant, T= Temp
First we need to find moles : n= m/MM The Molar Mass of N2= 28.02 moles/gram . The molar mass of O2= 32 moles/gram
Divide the respective masses by the Molar Masses
For N2: n = 73.8/28.02
n=2.63 moles N2
For O2: n= 52.9/32
n= 1.65 moles O2
Use the equation PV= nRT now, in terms of V
V= (nRT)/P
R= constant= 0.0821 (rounded), @STP Temp= 273k and P=1 atm
V of N2 will be:
[ (2.63)(.0821)(273) ] / 1
Volume of N2 = 58.7 Liters
For O2:
[ (1.65)(.0821)(273) ] / 1
Volume of O2 =37.0 Liters
Now we're going to use the equation PV= nRT, where P=pressure, V=volume, n= moles, R= constant, T= Temp
First we need to find moles : n= m/MM The Molar Mass of N2= 28.02 moles/gram . The molar mass of O2= 32 moles/gram
Divide the respective masses by the Molar Masses
For N2: n = 73.8/28.02
n=2.63 moles N2
For O2: n= 52.9/32
n= 1.65 moles O2
Use the equation PV= nRT now, in terms of V
V= (nRT)/P
R= constant= 0.0821 (rounded), @STP Temp= 273k and P=1 atm
V of N2 will be:
[ (2.63)(.0821)(273) ] / 1
Volume of N2 = 58.7 Liters
For O2:
[ (1.65)(.0821)(273) ] / 1
Volume of O2 =37.0 Liters
Thanks and regards
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mukesh sharma
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