Arun
Last Activity: 8 Years ago
Dear student
Here, Temperature, T = 300K
Final volume, Vf = 20 l
Initial volume, Vi = 5 l
Work done in an isothermal reversible process is given by
W = n*R*T ln(V2/V1)
= 1* 8.314* 298* ln(20/10)
= 1717.322 J
= 1.717 Kilo joule
Since, temperature is constant , ?U = 0, and hence Q = -W.
Therefore the heat absorbed by the gas is equal to the amount of work done.
This implies that heat absorbed by the gas, Q = -1.717 kJ.
Regards
Arun (askIITians forum expert)
