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Calculate the amount of work done by 2 miles of an ideal gas at 298 k in reversible isothermal expansion from 10 litre to 20 litre

Calculate the amount of work done by 2 miles of an ideal gas at 298 k in reversible isothermal expansion from 10 litre to 20 litre

Grade:11

1 Answers

Arun
25763 Points
3 years ago
Dear student
 
Here, Temperature, T = 300K
Final volume, Vf = 20 l
Initial volume, Vi = 5 l
Work done in an isothermal reversible process is given by
W = n*R*T ln(V2/V1)
 = 1* 8.314* 298* ln(20/10)
 = 1717.322 J
= 1.717 Kilo joule
Since, temperature is constant , ?U = 0, and hence Q = -W. 
Therefore the heat absorbed by the gas is equal to the amount of work done. 
This implies that heat absorbed by the gas, Q = -1.717 kJ. 
 
Regards
Arun (askIITians forum expert)

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