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        Calculate the amount of work done by 2 miles of an ideal gas at 298 k in reversible isothermal expansion from 10 litre to 20 litre
one year ago

Arun
22985 Points
							Dear student

Here, Temperature, T = 300KFinal volume, Vf = 20 lInitial volume, Vi = 5 lWork done in an isothermal reversible process is given by
W = n*R*T ln(V2/V1)
= 1* 8.314* 298* ln(20/10)
= 1717.322 J
= 1.717 Kilo joule
Since, temperature is constant , ?U = 0, and hence Q = -W. Therefore the heat absorbed by the gas is equal to the amount of work done. This implies that heat absorbed by the gas, Q = -1.717 kJ.

Regards


one year ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions