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Ball A is thrown vertically up from the ground at time t=0 with an initial velocity of 60m/sec. Ball B is thrown vertically up from ground at t=0 with an initial velocity of 45m/sec. Calculate the maximum distance between the two balls and the time (t) at which this occurs.


2 years ago

Eshan
2095 Points
							From the frame of ball B, ball A moves with up with constant speed of 60m/s-45m/s=15m/s upwards with no relative acceleration. So the distance will constantly increase until the ball B reaches the ground.Time of flight of ball B=Hence the maximum distance between the two balls in the time=

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions