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asic conversion formula: F = 9/5C + 32Our problem: 2C = FSubstitute F in the first formula with 2C from the second, which gives you:2C = 9/5C + 32Subtract 9/5C from both sides, which gives:2C - 9/5C = 32Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32Multiply 5 to each side, which leaves C = 160So, 160 degrees Celsius will equal 320 degrees Fahrenheit.
C = 5/9(F-32) or (F-32)/1.8
We want C = 2F or F = C/2
So C = (C/2 - 32)/1.8
1.8 C = C/2 - 32
1.3 C = -32
C = -24.6, F = -12.3
-24.6 degrees C = -12.3 degrees F. That’s rounded to the nearest tenth of a degree.
At what temperature the Fahrenheit scale reading equal to half of Celsius scale:
Basic conversion formula: F = 9/5C + 32Our problem: 2C = FSubstitute F in the first formula with 2C from the second, which gives you:2C = 9/5C + 32Subtract 9/5C from both sides, which gives:2C - 9/5C = 32Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32Multiply 5 to each side, which leaves C = 160
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