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At what temperature is the Fahrenheit scale reading equal to (a) twice that of the Celsius and (b) half that of the Celsius? At what temperature is the Fahrenheit scale reading equal to (a) twice that of the Celsius and (b) half that of the Celsius?
at -24.613 F temperature is the Fahrenheit scale reading equal to (a) twice that of the Celsius and at 160 F temperatuar is the Fahrenheit scale reading equal to (b) half that of the Celsius?
at -24.613 F temperature is the Fahrenheit scale reading equal to twice that of the Celsius and at 160 F temperatuar is the Fahrenheit scale reading equal to half that of the Celsius?
asic conversion formula: F = 9/5C + 32Our problem: 2C = FSubstitute F in the first formula with 2C from the second, which gives you:2C = 9/5C + 32Subtract 9/5C from both sides, which gives:2C - 9/5C = 32Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32Multiply 5 to each side, which leaves C = 160So, 160 degrees Celsius will equal 320 degrees Fahrenheit.
At what temperature is the Fahrenheit scale reading equal to twice that of the Celsius? C = 5/9(F-32) or (F-32)/1.8We want C = 2F or F = C/2So C = (C/2 - 32)/1.81.8 C = C/2 - 321.3 C = -32C = -24.6, F = -12.3-24.6 degrees C = -12.3 degrees F. That’s rounded to the nearest tenth of a degree.At what temperature the Fahrenheit scale reading equal to half of Celsius scale:Basic conversion formula: F = 9/5C + 32Our problem: 2C = FSubstitute F in the first formula with 2C from the second, which gives you:2C = 9/5C + 32Subtract 9/5C from both sides, which gives:2C - 9/5C = 32Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32Multiply 5 to each side, which leaves C = 160
C = 5/9(F-32) or (F-32)/1.8
We want C = 2F or F = C/2
So C = (C/2 - 32)/1.8
1.8 C = C/2 - 32
1.3 C = -32
C = -24.6, F = -12.3
-24.6 degrees C = -12.3 degrees F. That’s rounded to the nearest tenth of a degree.
At what temperature the Fahrenheit scale reading equal to half of Celsius scale:
Basic conversion formula: F = 9/5C + 32Our problem: 2C = FSubstitute F in the first formula with 2C from the second, which gives you:2C = 9/5C + 32Subtract 9/5C from both sides, which gives:2C - 9/5C = 32Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32Multiply 5 to each side, which leaves C = 160
As we know, the formula for interconversion between Fahrenheit and Celsius is F = 9/5 C + 32 (a) given, F = 2Chence,2C = 9/5 C + 32or, C/5 = 32or, C = 160o celsius which in Fahrenheit scale, F = 320 (b) given, F = C/2hence, C/2 = 9/5 C + 32or, – 2/5 C = 32or, C = – 80o celsius; which in fahrenheit scale is, F = -40 Hope it helps.Regards,Kushagra
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