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At what temperature is the Fahrenheit scale reading equal to (a) twice that of the Celsius and (b) half that of the Celsius?
at -24.613 F temperature is the Fahrenheit scale reading equal to (a) twice that of the Celsius and at 160 F temperatuar is the Fahrenheit scale reading equal to (b) half that of the Celsius?
at -24.613 F temperature is the Fahrenheit scale reading equal to twice that of the Celsius and at 160 F temperatuar is the Fahrenheit scale reading equal to half that of the Celsius?
asic conversion formula: F = 9/5C + 32Our problem: 2C = FSubstitute F in the first formula with 2C from the second, which gives you:2C = 9/5C + 32Subtract 9/5C from both sides, which gives:2C - 9/5C = 32Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32Multiply 5 to each side, which leaves C = 160So, 160 degrees Celsius will equal 320 degrees Fahrenheit.
At what temperature is the Fahrenheit scale reading equal to twice that of the Celsius? C = 5/9(F-32) or (F-32)/1.8We want C = 2F or F = C/2So C = (C/2 - 32)/1.81.8 C = C/2 - 321.3 C = -32C = -24.6, F = -12.3-24.6 degrees C = -12.3 degrees F. That’s rounded to the nearest tenth of a degree.At what temperature the Fahrenheit scale reading equal to half of Celsius scale:Basic conversion formula: F = 9/5C + 32Our problem: 2C = FSubstitute F in the first formula with 2C from the second, which gives you:2C = 9/5C + 32Subtract 9/5C from both sides, which gives:2C - 9/5C = 32Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32Multiply 5 to each side, which leaves C = 160
C = 5/9(F-32) or (F-32)/1.8
We want C = 2F or F = C/2
So C = (C/2 - 32)/1.8
1.8 C = C/2 - 32
1.3 C = -32
C = -24.6, F = -12.3
-24.6 degrees C = -12.3 degrees F. That’s rounded to the nearest tenth of a degree.
At what temperature the Fahrenheit scale reading equal to half of Celsius scale:
Basic conversion formula: F = 9/5C + 32Our problem: 2C = FSubstitute F in the first formula with 2C from the second, which gives you:2C = 9/5C + 32Subtract 9/5C from both sides, which gives:2C - 9/5C = 32Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32Multiply 5 to each side, which leaves C = 160
As we know, the formula for interconversion between Fahrenheit and Celsius is F = 9/5 C + 32 (a) given, F = 2Chence,2C = 9/5 C + 32or, C/5 = 32or, C = 160o celsius which in Fahrenheit scale, F = 320 (b) given, F = C/2hence, C/2 = 9/5 C + 32or, – 2/5 C = 32or, C = – 80o celsius; which in fahrenheit scale is, F = -40 Hope it helps.Regards,Kushagra
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