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At what temperature is the Fahrenheit scale reading equal to (a) twice that of the Celsius and (b) half that of the Celsius?

At what temperature is the Fahrenheit scale reading equal to (a) twice that of the Celsius and (b) half that of the Celsius?

Grade:upto college level

5 Answers

mazidur rahman
20 Points
4 years ago
at -24.613 F temperature is the Fahrenheit scale reading equal to (a) twice that of the Celsius and at 160 F temperatuar is the Fahrenheit scale reading equal to (b) half that of the Celsius?
mazidur rahman
20 Points
4 years ago
at -24.613 F temperature is the Fahrenheit scale reading equal to twice that of the Celsius and at 160 F temperatuar is the Fahrenheit scale reading equal to half that of the Celsius?
khadija
33 Points
3 years ago

asic conversion formula: F = 9/5C + 32
Our problem: 2C = F

Substitute F in the first formula with 2C from the second, which gives you:
2C = 9/5C + 32

Subtract 9/5C from both sides, which gives:
2C - 9/5C = 32

Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32

Multiply 5 to each side, which leaves C = 160

So, 160 degrees Celsius will equal 320 degrees Fahrenheit.

 

khadija
33 Points
3 years ago
 
At what temperature is the Fahrenheit scale reading equal to twice that of the Celsius?
 

C = 5/9(F-32) or (F-32)/1.8

We want C = 2F or F = C/2

So C = (C/2 - 32)/1.8

1.8 C = C/2 - 32

1.3 C = -32

C = -24.6, F = -12.3

-24.6 degrees C = -12.3 degrees F. That’s rounded to the nearest tenth of a degree.

At what temperature the Fahrenheit scale reading equal to half of Celsius scale:

Basic conversion formula: F = 9/5C + 32
Our problem: 2C = F

Substitute F in the first formula with 2C from the second, which gives you:
2C = 9/5C + 32

Subtract 9/5C from both sides, which gives:
2C - 9/5C = 32

Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32

Multiply 5 to each side, which leaves C = 160

Kushagra Madhukar
askIITians Faculty 629 Points
one year ago
As we know, the formula for interconversion between Fahrenheit and Celsius is 
F = 9/5 C + 32
 
(a) given, F = 2C
hence,
2C = 9/5 C + 32
or, C/5 = 32
or, C = 160o celsius which in Fahrenheit scale, F = 320
 
(b) given, F = C/2
hence, C/2 = 9/5 C + 32
or, – 2/5 C = 32
or, C = – 80o celsius; which in fahrenheit scale is, F = -40
 
Hope it helps.
Regards,
Kushagra
    
 

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