Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

at a certain temperature radius of an air bubble is doubled when it comes to the top from the bottom of a mercury column of of height 'h'. If the pressure at the top is two atmospheres, the value of h is?

at a certain temperature radius of an air bubble is doubled when it comes to the top from the bottom of a mercury column of of height 'h'. If the pressure at the top is two atmospheres, the value of h is?

Grade:11

1 Answers

Arun
25763 Points
3 years ago
Let the depth of lake be h cm
Pressure at the bottom of lake,
P1 = Atmospheric pressure + pressure due to water column in the lake
  = 76 × 13.6 × g + hρg
  = (76 × 13.6 + h × 1) g
Volume of bubble at the bottom, V1 = V
Volume of bubble at the surface, V2 = 2V
Pressure at the surface P2 = Atmospheric pressure
  = 76 cm of Hg
  = 76 × 13.6 × g
From Boyle's law, P1V1 = P2V2
(76 × 13.6 + h × 1) g × V = 76 × 13.6 × g× 2V
or h = (2 ×76 ×13.6) – (76 × 13.6)
  = 76 × 13.6
  = 1034 cm
  = 10.34 m

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free