Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

an ideal refrigerator runs etween – 23 C and 27 C find heat rejected to atmosphere for every joule of work

an ideal refrigerator runs etween – 23 C and 27 C find heat rejected to atmosphere for every joule of work
 

Grade:12

1 Answers

Khimraj
3007 Points
3 years ago
Let heat rejected is Q1 = x and W = 1J.
Then Q2 = Q1 – W = x-1
T1 = 27 C= 300 K.
T2 = -23 C = 250 K
For ideal process Q2/Q1 = T2/T1
x -1/x = 300/250
So x = 5J

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free