An ideal gas has molar heat capacity Cv at constant volume. The gas undergo the process T=To(1-aV) where a, To is constant and V is volume. Then molar heat capacity of the gas is

options are:
(a) Cv + R(1-aV)/aV
(B) Cv - R(1-aV)/aV
(c) Cv - R(1+aV)/2aV
(d) Cv + R(1+aV)/2aV

Question

TANISHA · Answer

why aint i gettin a reply?

keshav · Answer

C=Cv+(P*dV) /(ndT) C=Cv-R[R-(1-$V)]/[$V]$= alpha Hope it helps!! Feel free to ask any question... We will help you out as much as possible!!

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An ideal gas has molar heat capacity Cv at constant volume. The gas undergo the process T=To(1-aV) where a, To is constant and V is volume. Then molar heat capacity of the gas is options are: (a) Cv + R(1-aV)/aV (B) Cv - R(1-aV)/aV (c) Cv - R(1+aV)/2aV (d) Cv + R(1+aV)/2aV

An ideal gas has molar heat capacity Cv at constant volume. The gas undergo the process T=To(1-aV) where a, To is constant and V is volume. Then molar heat capacity of the gas is

options are:
(a) Cv + R(1-aV)/aV
(B) Cv - R(1-aV)/aV
(c) Cv - R(1+aV)/2aV
(d) Cv + R(1+aV)/2aV

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An ideal gas has molar heat capacity Cv at constant volume. The gas undergo the process T=To(1-aV) where a, To is constant and V is volume. Then molar heat capacity of the gas is options are: (a) Cv + R(1-aV)/aV (B) Cv - R(1-aV)/aV (c) Cv - R(1+aV)/2aV (d) Cv + R(1+aV)/2aV

An ideal gas has molar heat capacity Cv at constant volume. The gas undergo the process T=To(1-aV) where a, To is constant and V is volume. Then molar heat capacity of the gas is options are:(a) Cv + R(1-aV)/aV(B) Cv - R(1-aV)/aV(c) Cv - R(1+aV)/2aV(d) Cv + R(1+aV)/2aV

2 Answers

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An ideal gas has molar heat capacity Cv at constant volume. The gas undergo the process T=To(1-aV) where a, To is constant and V is volume. Then molar heat capacity of the gas is

options are:
(a) Cv + R(1-aV)/aV
(B) Cv - R(1-aV)/aV
(c) Cv - R(1+aV)/2aV
(d) Cv + R(1+aV)/2aV