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An ice cube of mass 0.1Kg is placed in an isolated container which is at 227oc .The specific heat S of the container varies with temperature T according to the empirical relation. S=A+BT,whereA=100cal/KgK and B=2*102 cal /KgK2.If the final temperature of the container is 270C.Determine the mass of the container.[Latent heat of fusion of water=8*104cal/Kg,specific of heat of water=103cal/Kg]
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