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An earthen pitcher loses 1g of water per minute due to evaporation. The water equivalent of the pitcher is 0.5kg and the pitcher contains 9.5g of water. Given that L v of water is 580 cal/g and specific heat of water is 1 cal/g 0 C, neglecting the radiation effects, show that the time required for water in the pitcher to cool from its original temperature of 30 0 C to 28 0 C is 34.5 minutes . Give me a detail answer


An earthen pitcher loses 1g of water per minute due to evaporation. The water equivalent of the pitcher is 0.5kg and the pitcher contains 9.5g of water. Given that Lv of water is 580 cal/g and specific heat of water is 1 cal/g0C, neglecting the radiation effects, show that the time required for water in the pitcher to cool from its original temperature of 300C to 280C is 34.5 minutes.
                    Give me a detail answer


Grade:10

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