saransh
Last Activity: 8 Years ago
this is a basic question
given : adiabatic hence Q= 0
co efficient of restitution e=1
friction = 0
v =initial vel of ball
restitution eqn v= u2 – u1
momentum conservation v = u2+ u1
u1= u2= v/2
energy conservvation ½ m(v/2)2 = 3/2 nRT1 – T2+ 0
WD + Q = E
T1 – T2 = mv2/12nR