All the rods have same conductance K and same Area of cross-section A. If ends A and C are maintained at temp 2T and T respectively. then find which of the following correct: A)rate of heat flow through ABC AOC and ADC is same B)rate of heat flow through BO and OD is same C)Total rate of heat flow from A to C is 3KAT/2a D) temp at junction B O and D are same

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Rajat · Answer

Option B is correct as BO and OD are symmetrical with respect to AC. Thus rate of heat flow thorough BO and OD is equal. Please upvote.

Khimraj · Answer

By symmetry I A B = I B C & I A D = I D C ∴ no current in BO and OD ∴ T B = T O = T D ...................................................................................

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