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A wire is suspended vertically from a rigid support.when loaded with a steel weight in air, the wire extend by 16cm.when the weight is completely immersed in water,the extension is reduced to 14 cm . The relative density of the material of the weight is (in gm/cm^3)?

A wire is suspended vertically from a rigid support.when loaded with a steel weight in air, the wire extend by 16cm.when the weight is completely immersed in water,the extension is reduced to 14 cm . The relative density of the material of the weight is (in gm/cm^3)?

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Grade:11

2 Answers

Eshan
askIITians Faculty 2095 Points
2 years ago
From Young’ s theory, the extension in the string is directly proportional to the tension in the string.

When weight is in air,T=mg

When weight is immersed in water,T'=mg-V\rho g=Vdg-V\rho g=mg(1-\dfrac{\rho}{d})

\implies 1-\dfrac{\rho}{d}=\dfrac{14}{16} \implies 1-\dfrac{1}{\rho_{rel}}=\dfrac{14}{16} \implies\rho_{rel}=8
Gitanjali Rout
184 Points
2 years ago
\implies 1-\dfrac{\rho}{d}=\dfrac{14}{16} \implies 1-\dfrac{1}{\rho_{rel}}=\dfrac{14}{16} \implies\rho_{rel}=8T`=mg-V\rho g=Vdg-V\rho g=mg(1-\dfrac{\rho}{d})When weight is immersed in water,T=mgFrom Young’ s theory, the extension in the string is directly proportional to the tension in the string.When weight is in air,

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