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Grade 11Thermal Physics

A wire is suspended vertically from a rigid support.when loaded with a steel weight in air, the wire extend by 16cm.when the weight is completely immersed in water,the extension is reduced to 14 cm . The relative density of the material of the weight is (in gm/cm^3)?

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Sourabh

9 Years agoGrade 11

2 Answers

Eshan

8 Years ago

From Young’ s theory, the extension in the string is directly proportional to the tension in the string.

When weight is in air, $T=mg$

When weight is immersed in water, $T'=mg-V\rho g=Vdg-V\rho g=mg(1-\dfrac{\rho}{d})$

$\implies 1-\dfrac{\rho}{d}=\dfrac{14}{16} \implies 1-\dfrac{1}{\rho_{rel}}=\dfrac{14}{16} \implies\rho_{rel}=8$

Gitanjali Rout

8 Years ago

$\implies 1-\dfrac{\rho}{d}=\dfrac{14}{16} \implies 1-\dfrac{1}{\rho_{rel}}=\dfrac{14}{16} \implies\rho_{rel}=8$ $T`=mg-V\rho g=Vdg-V\rho g=mg(1-\dfrac{\rho}{d})$ When weight is immersed in water, $T=mg$ From Young’ s theory, the extension in the string is directly proportional to the tension in the string.When weight is in air,

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