Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the solution to your problem below.
Latent heat of vapourisation of water at 0oC, L1 = 2.10×106 J/kg
= 2.10×103 J/g
Latent heat of fusion of ice, L2 = 3.36×105 J/kg
= 3.36×102 J/g
Let mass of ice formed = m gram
Then mass of water evaporated = (100 – m) gram
As no water is left in the vessel, Heat gained by water in evaporation = heat lost by water in freezing
or, (100 – m)L1 = mL2
or, (100 – m) × 2.10×103 = m × 3.36×102
Hence, m = 86.2 g
Thanks and regards,
Kushagra