Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping

A steel rail 30m long is firmly attched to the rod bed only at its ends. the sun raise the temperature of the rail by 50 0 C causing the rail to buckle. Assuming that the buckled rail consist of two straight parts melting in the centre, calculate how much the centre of the rail rise?(coefficient of linear expansion of steel=12*10 -6 )

A steel rail 30m long is firmly attched to the rod bed only at its ends. the sun raise the temperature of the rail by 500 C causing the rail to buckle. Assuming that the buckled rail consist of two straight parts melting in the centre, calculate how much the centre of the rail rise?(coefficient of linear expansion of steel=12*10-6)
 

Grade:11

1 Answers

Vikas TU
14149 Points
3 years ago
Dear Student,
From the formulae we know,
∆l=lα∆t
=30x12x10-6x50
=0.018
l’=l+∆l
=30.018
the centre will rise by = √(〖30.018〗^2-30^2)
=1.039m rise.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Thermal Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Register ICAT

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More