A steel rail 30m long is firmly attched to the rod bed only at its ends. the sun raise the temperature of the rail by 50⁰C causing the rail to buckle. Assuming that the buckled rail consist of two straight parts melting in the centre, calculate how much the centre of the rail rise?(coefficient of linear expansion of steel=12*10^-6)

Question

Vikas TU · Answer

Dear Student,
From the formulae we know,

∆l=lα∆t

=30x12x10-6x50

=0.018

l’=l+∆l

=30.018

the centre will rise by = √(〖30.018〗^2-30^2)

=1.039m rise.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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