Jitender Pal
Last Activity: 11 Years ago
Sol. r = 1 cm = 1 × 10^–3 m
A = 4π(10^–2)^2 = 4π × 10^–4 m^2
E = 0.3, σ = 6 * 10^-8
E/t = Aσe(T base 1^4 – T base 2^4)
= 0.3 × 6 × 10^–8 × 4π × 10^–4 × [(100)^4 – (300)^4]
= 0.3 × 6 × 4π × 10^–12 × [1 – 0.0081] × 10^12
= 0.3 × 6 × 4 × 3.14 × 9919 × 10^–4
= 4 × 18 × 3.14 × 9919 × 10^–5 = 22.4 ≈ 22 W