 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A real engine has an efficiency of 33%. The engine has a work output of 24 j per cycle (a) How much hear energy is extracted from the high temperature reservoir per cycle      (A) 8 J                  (B) 16 J               (C) 48 J                               (D)72 J                                                         (E) the question can be answered only if theengine is a carnot engine.     (b) How much heat energy is discharged into the low temperature reservoir per cycle?                                                           (A) 8 J  (B) 16 J               (C) 48 J               (D) 72 J               (E) the question can be answered only if the engine is a carnot engine.(c) For this engine TL = 27ºC. What can be concluded about TH? (A) TH   = 450ºC              (B)TH=177ºC.                                                                                                              (C) TH > 177ºC.               (D)TH(E) 177ºC H `
4 years ago 396 Points
```							(a) The correct option is (D) 72 J.The efficiency ε of a Carnot engine is defined as,  ```
4 years ago
```							As the formula of efficiency is only applicable to Carnot engines and as this is a real engine the first two questions cannot be answered. Thus  option E for both.If it were a Carnot`s engine, then TH would have been 177°C . Considering a Carnot`s engine having The as 177 C would give efficiency of 33% but as this is a real engine its efficiency must be less than 33%. Hence if it is 33% then it`s TH must be greater than 177°C.
```
2 years ago
```							The answer for first two can be given by the formula e= W/Qh1/3= 24/QhQh=72J1/3=1-Ql/QhQl= 48JPardon my previous answer was wrong.The third part is pretty much fine.
```
2 years ago
```							For the third part, if the efficiency is less than a Carnot`s engine, for a Carnot`s engine its The would be 177C e=W/Qh Qh proportional to Th hence e is inversely proportional to Th thus as e is less than will be more than 177C
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Thermal Physics

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions