Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Let density of metal and mercury be d1andd2 respectively.
Fraction of volume of metal submerged initially =d1d2 .....(1)
We know that Volume of metal will change after increase of temperature ΔT by a factor (1+γ1ΔT)Similarly Volume of mercury will change after increase of temperature ΔT by a factor (1+γ2ΔT)
(It is assumed that γ is coefficient of volume expansion.)
Density of metal after increase of temperature ΔT=d11+γ1ΔTDensity of mercury after increase of temperature ΔT=d21+γ1ΔT
Fraction of volume of metal submerged after increase of temperature =d11+γ1ΔTd21+γ2ΔT=d1d2(1+γ2ΔT1+γ1ΔT) .....(2)
Change in fraction of volume of metal submerged =d1d2(1+γ2ΔT1+γ1ΔT)−d1d2=d1d2(1+γ2ΔT1+γ1ΔT−1)
=d1d2(1+γ2ΔT)−(1+γ1ΔT)(1+γ1ΔT)=d1d2(γ2−γ1)ΔT1+γ1ΔT
Factor of the fraction of the volume of the metal submerged in mercury changed after increase of volume=d1d2(γ2−γ1)ΔT1+γ1ΔTd1d2=(γ2−γ1)ΔT1+γ1ΔT
please approve this
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !