Grade 9Thermal Physics

A mixture of 2 moles of helium gas (atomic mass = 4 amu) and 1 mole of argon gas (atomic mass = 40 amu) is kept at 300 K in a container. The ratio of the rms speeds

Leo Pixie

12 Years agoGrade 9

2 Answers

Arun Kumar

12 Years ago

Hello Student,

v=root(3rt/m)
=>ratio =root(m_argon/m_helium)=root(10)

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

Kushagra Madhukar

5 Years ago

Dear student,

Please find the solution to your problem below.

v_rms = √(3RT/M)

=>ratio = √(M_Ar/M_He) = √10 : 1 = 3.16 : 1

Thanks and regards,

Kushagra

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A mixture of 2 moles of helium gas (atomic mass = 4 amu) and 1 mole of argon gas (atomic mass = 40 amu) is kept at 300 K in a container. The ratio of the rms speeds

Leo Pixie

2 Answers

Arun Kumar

Kushagra Madhukar

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