Flag Thermal Physics> a metal rod of length 20 cm and area of c...
question mark

a metal rod of length 20 cm and area of cross section 0.8*10^-4 m^2is heated at one end for 100 degree celcius and other end at 30 degree celcius , the quantity of heat flow in 5 minute along the rod is 3.3*10^3 joule determine the thermal conductivity

santhosh , 7 Years ago
Grade 12th pass
anser 1 Answers
Varali

Last Activity: 7 Years ago

As you can see that the heat flowing through the rod in 5 mins(300sec) is actually the heat current=Q/t where Q is the heat flow and t is the time... So 3.3*10^5/300=0.011*10^5jouleper sec . Now heat current = thermal conductivity *(T1-T2)*area of cross section/length of rod . Therefore thermal conductivity = heatflow*length of rod/(T1-T2)* Area of cross section . Answer =0.011 *10^5*0.2 m/(100-30)*0.8*10^-4 =0.3928*10^5

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...