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A metal ball immersed in alcohol weighs W1 at 0ºC and W2 at 59ºC. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of metal is large compared to that of alcohol, it can be shown that A. W1 > W2 B. W1 = W2 C. W1 D. W2 = (W1 / 2)

A metal ball immersed in alcohol weighs W1 at 0ºC and W2 at 59ºC. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of metal is large compared to that of alcohol, it can be shown that

A. W1 > W2

B. W1 = W2

C. W1

D. W2 = (W1 / 2)

Grade:12

1 Answers

Arun
25763 Points
2 years ago
Dear student
 
Given cubical expansion of metal is less than that of alcohol so Alchohol expands more than metal. So comparitively density of Alchohol is less than metal. So upward force becomes lesser when temperature is increased and W2 > W1

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