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Grade: 11
        A liquid takes 10 minute to cool from 70℃ to 50℃ how much time will it take to cool from 60℃ to 40℃ temperature is surrounding is 20℃
one year ago

Answers : (2)

HARDIK
6 Points
							APPLYING NEWTON’S LAW OF MOTION,
WE GET,
(70-50)/(10.60)=K((70+50)/2-20)            ........(1)
(60-40)/T= K((60+40)/2-20)                 ........(2)
EQN (1)/EQN.(2)
T/(10.60)=40/30
T = 80 SECONDS.

REGARDS
HARDIK BAWEJA
 
NOTE: PLEASE CHECK ANY CALCULATION ERROR AND ASK AGAIN IF NOT CLEAR...
ALL THE BEST!!
one year ago
Arun
22782 Points
							Dear Amar
 
According to Newton's law of cooling, we have
mc (T1 - T2)/t = k [(T1 + T2)/2 -  T0)]        -------(1)
mc/k  =[(T1 + T2)/2 - T0)]/[(T1 - T2)/t]
mc/k = [(70+50)/2 - 20)]/[(70 - 50)/10]
        = 60 / 2 = 30
Substituting T1 = 60 and T2 = 40 and T0 = 20  (all in °C) in Eq. (1), we get
mc (60 - 40)/t = k [(60+ 40)/2   -  20)]
20 mc/t  = 30 k
t = 20 mc/(30k)
  = (20/30) * 30
  = 600 /30 min
 = 20 min
The body takes 20 min to cool from 60°C to 40 °C. 
one year ago
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