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A liquid P of specific heat capacity 2400 J kg-1Kg-1And at 70c is mixed with another liquid R specifi heat capacity 1000 J kg-1 K-1 at 30c After mixing the final temperature of the mixture is 40c find the ratio of the mass of liquid mixed
according to question,heat loss by p = heat gain by rso , P.2400.30=R.1000.10 => P/R=5/36 Hopre this will help you Thanks and Regards Adarsh
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