0

Guest

Courses New

a glass tube has mercury thread of length 100 cm at 0°C and 101.55cm at 100°C.if real expansion of mercury is 1.85*10^-4/C° .what is coefficient of linear expansion of glass.

a glass tube has mercury thread of length 100 cm at 0°C and 101.55cm at 100°C.if real expansion of mercury is 1.85*10^-4/C° .what is coefficient of linear expansion of glass.

Grade:12

1 Answers

Eshan
askIITians Faculty 2095 Points
4 years ago
Dear student,

The change in length of mercury in glass tube is given as

\Delta L=L_0\gamma_r\Delta T

\implies \gamma_r=0.55\times 10^{-4}/^{\circ}C
But\implies \gamma_r=\gamma_{Hg}-\gamma_{glass}
\implies \gamma_{glass}=1.3\times 10^{-4}/^{\circ}C=3\alpha_{glass}
\implies \alpha_{glass}=4.3\times 10^{-5}/^{\circ}C

Think You Can Provide A Better Answer ?

Other Related Questions on Thermal Physics

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More