badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

a glass tube has mercury thread of length 100 cm at 0°C and 101.55cm at 100°C.if real expansion of mercury is 1.85*10^-4/C° .what is coefficient of linear expansion of glass.

3 years ago

Answers : (1)

Eshan
askIITians Faculty
2095 Points
							Dear student,

The change in length of mercury in glass tube is given as

\Delta L=L_0\gamma_r\Delta T

\implies \gamma_r=0.55\times 10^{-4}/^{\circ}C
But\implies \gamma_r=\gamma_{Hg}-\gamma_{glass}
\implies \gamma_{glass}=1.3\times 10^{-4}/^{\circ}C=3\alpha_{glass}
\implies \alpha_{glass}=4.3\times 10^{-5}/^{\circ}C

2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details