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A faulty thermometer has fixed points at 0.2°c and 101.7°c. What would be the correct reading corresponding to a temperature of 60°c by the thermometer?
Here faulty reading (x)=60Lower fixed point of faulty readind (L.F.P)=0.2Upper fixed point of faulty reading (U.F.P.)=101.7Fundamental interval (F.I.)=101.7 – 0.2 = 101.5Correct reading(C)=?c/100*(x-L.F.P)/F.I.C/100=59.8/101.5 = 0.589C=0.589*100=58.9 celsius scale
usually the thermometer fixed points basically are:Lower point =0°cUpper point=100°cso in between there are 100 divisions.each one division corresponds to 1°cBut in the above mentioned case :Lower point=0.2°cupper point=101.7°cso total division=101.7-0.2 = 101.5thus, 1 degree= 1 division=100/101.5Now let us find the given temperature:measured temperature 60 °c=100x60/101.5=59.11°cHope it is clear.
HELLO THERE! Here’s the generalized formula: Let C be the correct reading,L be the lower point of faulty thermometer,U be the upper point of faulty thermometer,x be the given faulty reading. THANKS!
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