Let the density of the liquid in the bottle be d.
Given that, m1=104gm.
                     t1=34celsius
                    m2=m1+4.5
                         =104+4.5
                          =108.5
                    t2=100celsius
we know that the coefficient of apparent expansion=(V2-V1)/V1.(t2-t1)
                                                                                           =(m2/d-m1/d)/m1/d(t2-t1)
                                                                                           =(108.5/d-104/d)/104/d(66) 
                                                                                           =(4.5/d)/104*66/d
                                                                                           =4.5/(104*66)
                                                                                           =4.5/6864
                                                                                           =6.55*10^-4
						

							here the density of liquid is constant 
we know      ??V=V1????t       ??V/V=????t
we also know   d=m/V   since d is constant ,
??V/V=??m/m                                     ??m=4.5gm m=104gm  ??t=66°C
??=(??V/V)/??t
??=(??m/m)/??t
   =(4.5/104)/66
    =6.5559*10?4
    ??=0.0006559 /°C
approx.   ?? = 0.0007 /°C