L JAIPAL REDDY
Last Activity: 6 Years ago
Q1=E1*A* σ(T14-T24)
210=E1*A* σ(5004-3004)...........(1)
700=E2*A* σ(5004-3004)............(2) {Emissivity of the black body is equal to 1, i.e E2=1}
σ= 5.67*10-8 W/M2-K4
SUB VALUES IN EQ 2, WE GET A2=0.226.........(3)
NOE, SUB A IN EQ 1, WE GET, E1=0.30125