a carnot engine whose efficiency is 50 %,if sink temperature is decreased by 100% then efficiency will be 70% ,find the temperature of source

Question

Shailendra Kumar Sharma · Answer

1-Tsink/TSource =.5 How can you reduce temp by 100% still lets say you reduced to half 1-(.5Tsink)/Tsource =.9 This gives (TSource-Tsink)/(Tso-.5Tsi) =5/9 4Tsource=(6.5) Tsink This way you can proceed

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a carnot engine whose efficiency is 50 %,if sink temperature is decreased by 100% then efficiency will be 70% ,find the temperature of source

a carnot engine whose efficiency is 50 %,if sink temperature is decreased by 100% then efficiency will be 70% ,find the temperature of source

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a carnot engine whose efficiency is 50 %,if sink temperature is decreased by 100% then efficiency will be 70% ,find the temperature of source

a carnot engine whose efficiency is 50 %,if sink temperature is decreased by 100% then efficiency will be 70% ,find the temperature of source

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