A calorimeter contains 250 gram of water at odegr

Question

A calorimeter contains 250 gram of water at odegree c and 15 gm of ice at o degree c now steam at 100 degree cis 5 into it continuously till the temperature of the content become 15 degrees calculate the amount of stamp required if water equivalent of the calorimeter loss suffered due to radiation is negligible

Shiv Sagar · Accepted Answer

Since final temperature is 15 degrees, all the substances reach that state. Heat absorbed by 250g water at 0 degrees = 250 x 1 x (15 – 0)= 3750 calHeat absorbed by 15g ice = 15 x 80 [latent heat] + 15 x 1 x (15 – 0) = 1425 cal This heat will be provided by an amout “m” of steam that we poured and have to calculate. Heat lost by “m” mass of steam = m x 540 + m x 1 x (100 – 15) = 615 x mThis is equal to 3750 + 14253750 +1425 = 615m,m = 8.414g

Thermal Physics> A calorimeter contains 250 gram of water ...

Rohit kumar , 5 Years ago

Shiv Sagar

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Thermal Physics> A calorimeter contains 250 gram of water ...

Rohit kumar , 5 Years ago

Shiv Sagar

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