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Grade 11Thermal Physics

A bulb of 3 litre capacity filled with air is heated from 27°C to t°C. The air this expelled measures 1.45L at 17°C. Considering the pressure to be constant 1 atm throughout and ignoring the expansion of bulb, calculate t.

Pranav mohril

9 Years agoGrade 11

1 Answer

musafir

8 Years ago

$\frac{P_{300}V_{300}}{n_{300}300}=\frac{P_{t}V_{t}}{n_{t}t}$

P₃₀₀= P_t= 1 atm

V₃₀₀= 3L

V_t = 3L+x (x is expanded volume)

n₃₀₀=n_t

_so:

Rearrange them

Given:

$\frac{1.45}{290}=\frac{x}{t}$

$x=\frac{1.45\times t}{290}------(2)$

Put the value of x from equation (2) to equation (1) and solve for t

t=600K

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