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# A bulb of 3 litre capacity filled with air is heated from 27°C to t°C. The air this expelled measures 1.45L at 17°C. Considering the pressure to be constant 1 atm throughout and ignoring the expansion of bulb, calculate t.

musafir
11 Points
3 years ago
$\frac{P_{300}V_{300}}{n_{300}300}=\frac{P_{t}V_{t}}{n_{t}t}$

P300 = Pt = 1 atm
V300 = 3L
Vt = 3L+x (x is expanded volume)
n300=n
so:
$\frac{3}{300}=\frac{3+x}{t}$

Rearrange them

$t=\frac{300\times (3+x)}{3}----(1)$
Given:

$\frac{V_{290}}{T_{290}}=\frac{V_{t}}{t}$

$\frac{1.45}{290}=\frac{x}{t}$
$x=\frac{1.45\times t}{290}------(2)$
Put the value of x from equation (2) to equation (1) and solve for t
t=600K