0

Guest

Courses New

A block of mass 20 kg is moved with constant velocity along an inclined plane of inclination 37° with help of a force of constant power 50 W. If the coefficient of kinetic friction between block and surface is 0.25, then what fraction of power is used against gravity?

A block of mass 20 kg is moved with constant velocity along an inclined plane of inclination 37° with help of a force of constant power 50 W. If the coefficient of kinetic friction between block and surface is 0.25, then what fraction of power is used against gravity?

Grade:12th pass

2 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
From equilibrium of forces along the incline,
mgsin\theta+\mu mg cos\theta=F
\implies F=160N
Power=Fv=constant=50W
\implies v=\dfrac{5}{16}m/s
Power used against gravity=\vec{F_g}.\vec{v}=-mgsin\theta v=37.5W
Hence fraction of power used=75%%

Gitanjali Rout
184 Points
5 years ago
From equilibrium of forces along the incline,
mgsin\theta+\mu mg cos\theta=F
\implies F=160N
Power=Fv=constant=50W
\implies v=\dfrac{5}{16}m/s
Power used against gravity=\vec{F_g}.\vec{v}=-mgsin\theta v=37.5W
Hence fraction of power used=75%%

Think You Can Provide A Better Answer ?

Other Related Questions on Thermal Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More