A beaker containing 200g of water. The heat capacity of the beaker is equal to that of 20g water. The initial temperature of water in the beaker is 20°C. If 440g of hot water at 92°C is poured in,the final temperature(neglecting radiation loss) will be nearly

Question

MPRANEETH · Answer

we knowthat principle of calorimetry :heat lossed by the hotbody is equal to heat gained by the cold body there we know that Q=mc(dt) therefore equating to theheat gained by cold body given total mass is (200+20)(T-20)=440*((92-T)) THEREFORE ON SIMPLIFYING WE GET T =68 iassumed the final temperature T

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

A beaker containing 200g of water. The heat capacity of the beaker is equal to that of 20g water. The initial temperature of water in the beaker is 20°C. If 440g of hot water at 92°C is poured in,the final temperature(neglecting radiation loss) will be nearly

A beaker containing 200g of water. The heat capacity of the beaker is equal to that of 20g water. The initial temperature of water in the beaker is 20°C. If 440g of hot water at 92°C is poured in,the final temperature(neglecting radiation loss) will be nearly

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Thermal Physics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship