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A beaker containing 200g of water. The heat capacity of the beaker is equal to that of 20g water. The initial temperature of water in the beaker is 20°C. If 440g of hot water at 92°C is poured in,the final temperature(neglecting radiation loss) will be nearly
we knowthat principle of calorimetry :heat lossed by the hotbody is equal to heat gained by the cold bodythere we know that Q=mc(dt)therefore equating to theheat gained by cold bodygiven total mass is (200+20)(T-20)=440*((92-T))THEREFORE ON SIMPLIFYING WE GET T =68iassumed the final temperature T
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