A and B are two points on a uniform metal ring whose centre is O. The angle AOB=theta. A and B are maintained at two different constant temperature. When theta=180°, the net rate of total heat flow from A to B is 1.2 W. When theta=90°, this rate will be

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Arun · Answer

Dear student I am getting my answwr as 1.6 W.Please check and let me know if I am correct. Regards. Arun

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ADNAN MUHAMMED

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A and B are two points on a uniform metal ring whose centre is O. The angle AOB=theta. A and B are maintained at two different constant temperature. When theta=180°, the net rate of total heat flow from A to B is 1.2 W. When theta=90°, this rate will be

A and B are two points on a uniform metal ring whose centre is O. The angle AOB=theta. A and B are maintained at two different constant temperature. When theta=180°, the net rate of total heat flow from A to B is 1.2 W. When theta=90°, this rate will be

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A and B are two points on a uniform metal ring whose centre is O. The angle AOB=theta. A and B are maintained at two different constant temperature. When theta=180°, the net rate of total heat flow from A to B is 1.2 W. When theta=90°, this rate will be

A and B are two points on a uniform metal ring whose centre is O. The angle AOB=theta. A and B are maintained at two different constant temperature. When theta=180°, the net rate of total heat flow from A to B is 1.2 W. When theta=90°, this rate will be

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