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A 1.0 mol sample of an ideal gas is kept at 0.0^0 C during an expansion from 3.0L TO 10.0L.
how much work is done by the gas during the expansion?

hilal shah , 4 Years ago
Grade 12th pass
anser 2 Answers
Pawan Prajapati

Last Activity: 4 Years ago

Answer ::

As, the temperature of gas is fixed.
This process is isothermal.

Now,
work done (W) = nRT ln ( V2/V1)
= (1)(8.31)(273)ln ( 3/10)
= - 2.7 × 10^3 J.

Thanks

?? ?

Last Activity: 2 Years ago

As, the temperature of gas is fixed.
This process is isothermal.
 
 
work done (W) = nRT ln ( Vf/Vi)
= (1)(8.31)(273)ln ( 10/3)
=  2.7 × 10^3 J.

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