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A 1.0 mol sample of an ideal gas is kept at 0.0^0 C during an expansion from 3.0L TO 10.0L. how much work is done by the gas during the expansion? A 1.0 mol sample of an ideal gas is kept at 0.0^0 C during an expansion from 3.0L TO 10.0L.how much work is done by the gas during the expansion?
Answer ::As, the temperature of gas is fixed.This process is isothermal.Now, work done (W) = nRT ln ( V2/V1) = (1)(8.31)(273)ln ( 3/10) = - 2.7 × 10^3 J.Thanks
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