60g of ice at 0°C is mixed with 60g of steam at 100°C.At thermal equilibrium the mixture contains?

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Arun · Answer

There is no water because of steam the 60 gms ice turn into steam Therefore 60 +60 =120 gms 120 gms steam formed

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60g of ice at 0°C is mixed with 60g of steam at 100°C.At thermal equilibrium the mixture contains?

60g of ice at 0°C is mixed with 60g of steam at 100°C.At thermal equilibrium the mixture contains?

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60g of ice at 0°C is mixed with 60g of steam at 100°C.At thermal equilibrium the mixture contains?

60g of ice at 0°C is mixed with 60g of steam at 100°C.At thermal equilibrium the mixture contains?

1 Answers

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