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5g of ice at -10°c is put in 100g of water at 30°c in a container having water equivalent 20g. Find the final temperature of the mixture (specific heat of ice=0.5calg-°c-

Sagar , 8 Years ago
Grade 11
anser 1 Answers
Eshan
Loss in heat of water+container=Gain in heat of ice

\implies (5)(0.5)(10)+(5)(10)+(5)(1)(T-0)=(120)(1)(30-T)
\implies T=25.4^{\circ}C
Last Activity: 7 Years ago
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