¬2 moles of an ideal monoatonic gas is carried from a state (P0,V0) to a state (2P0,2V0) along a straight line path in a P-V diagram.The amount of heat absorbed by the gas in the process is given by: (a) 3P0V0 (b) (9/2)P0V0 (c) 6P0V0 (d) (3/2)P0V0

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Khimraj · Answer

U = nC v T = n(3R/2)(4P o V o – P o V o )/nR = 9P o V o /R W = (2P o +P o )V o /2 = 3P o V o /2 Q = W + U = 6P o V o Hope it clears. If you like answer then please approve it.

Aastha Singh · Answer

dear student, kindly refer to the image below to get detailed solution apply 1 st law of thermodynamics q= delU+ W

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¬2 moles of an ideal monoatonic gas is carried from a state (P0,V0) to a state (2P0,2V0) along a straight line path in a P-V diagram.The amount of heat absorbed by the gas in the process is given by: (a) 3P0V0 (b) (9/2)P0V0 (c) 6P0V0 (d) (3/2)P0V0

¬2 moles of an ideal monoatonic gas is carried from a state (P0,V0) to a state (2P0,2V0) along a straight line path in a P-V diagram.The amount of heat absorbed by the gas in the process is given by: (a) 3P0V0 (b) (9/2)P0V0 (c) 6P0V0 (d) (3/2)P0V0

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