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¬2 moles of an ideal monoatonic gas is carried from a state (P0,V0) to a state (2P0,2V0) along a straight line path in a P-V diagram.The amount of heat absorbed by the gas in the process is given by: (a) 3P0V0 (b) (9/2)P0V0 (c) 6P0V0 (d) (3/2)P0V0
U = nCvT = n(3R/2)(4PoVo – PoVo)/nR = 9PoVo/RW = (2Po +Po)Vo/2 = 3PoVo/2Q = W + U = 6PoVoHope it clears. If you like answer then please approve it.
dear student,kindly refer to the image below to get detailed solutionapply 1st law of thermodynamicsq= delU+ W
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