1kg of ice at -20'c is mixed with 2kg of water at 90'c. Assuming that there is no energy loss to the environment what will be the final temp of the mixture? Latent heat of ice =334.4kJ/kg specific heat of water and ice are 4.18kJ/kg K and 2.09kJ/kgK resp

Arun
25758 Points
4 years ago
Dear student

mi si $\Delta$T + mi L + mi sw (T-0) = mw sw (90 -T)
1 * 2.09 *20 + 1 * 334.4 + 1 *4.18 * T =  2 * 4.18 * (90 -T)

T = 60 - 3p = 30 °c

Regards