1kg of ice at -20'c is mixed with 2kg of water at 90'c. Assuming that there is no energy loss to the environment what will be the final temp of the mixture? Latent heat of ice =334.4kJ/kg specific heat of water and ice are 4.18kJ/kg K and 2.09kJ/kgK resp

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Arun · Answer

Dear student m i s i T + m i L + m i s w (T-0) = m w s w (90 -T) 1 * 2.09 *20 + 1 * 334.4 + 1 *4.18 * T = 2 * 4.18 * (90 -T) T = 60 - 3p = 30 °c Regards Arun (askIITians forum expert)

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1kg of ice at -20'c is mixed with 2kg of water at 90'c. Assuming that there is no energy loss to the environment what will be the final temp of the mixture? Latent heat of ice =334.4kJ/kg specific heat of water and ice are 4.18kJ/kg K and 2.09kJ/kgK resp

1kg of ice at -20'c is mixed with 2kg of water at 90'c. Assuming that there is no energy loss to the environment what will be the final temp of the mixture? Latent heat of ice =334.4kJ/kg specific heat of water and ice are 4.18kJ/kg K and 2.09kJ/kgK resp

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1kg of ice at -20'c is mixed with 2kg of water at 90'c. Assuming that there is no energy loss to the environment what will be the final temp of the mixture? Latent heat of ice =334.4kJ/kg specific heat of water and ice are 4.18kJ/kg K and 2.09kJ/kgK resp

1kg of ice at -20'c is mixed with 2kg of water at 90'c. Assuming that there is no energy loss to the environment what will be the final temp of the mixture? Latent heat of ice =334.4kJ/kg specific heat of water and ice are 4.18kJ/kg K and 2.09kJ/kgK resp

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