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1 gm of ice requires 334 joules of heat to change it into water as we know specific heat of water is 4.2J/gk
1 gm of water is converted into steam by giving 2230J/g of heat energy specific heat of steam is 1.996kj/kg k.
For attaining equilibrium temperature= ice to water latent heat + water latent heat to change to 0degree to 100degree change in temperature /latent heat of vaporization
Mass of steam =334+ 420/2230=0.338g.
Q=m×c×t
80 degree Celsius final temperature
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